Find the general solution of each of the following equations:
(i) 4cos2 x = 1
(ii) 4sin2 x – 3 = 0
(iii) tan2 x = 1
To Find: General solution.
(i) Given: 4cos2 x = 1
cos2 x = ![]()
cos2 x = cos2![]()
Formula used: cos2
= cos2
= n
, n
I
By using the above formula, we have
x = n
, n
I
So the general solution is x = n
where n
I
(ii) Given: 4sin2 x – 3 = 0
sin2 x =
= sin2![]()
sin2 x = sin2![]()
Formula used: sin2
= sin2
= n
, n
I
By using the above formula, we have
x = n
, n
I
So the general solution is x = n
where n
I
(ii) Given: tan2 x = 1
tan2 x = tan2 ![]()
tan2 x = tan2 ![]()
The formula used: tan2
= tan2
= n
, n
I
By using the above formula, we have
x = n
, n
I
So the general solution is x = n
where n
I
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