Q11 of 21 Page 608

Find the general solution of each of the following equations:

4sin x cos x + 2sin x + 2cos x + 1 = 0


To Find: General solution.


Given: 4sin x cos x + 2sin x + 2cos x + 1 = 0 2sin x(2cos x + 1) + 2cos x + 1 = 0


So (2cos x + 1)( 2sin x + 1) = 0


cos x = = cos() or sin x = = sin


Formula used: cos = cos = 2n or sin = sin = m + (-1)m where n,m I


x = 2n or x = m +(-1)m . where n, m I


So the general solution is x =2n or x = m +(-1)m . where n, m I


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