Verify that A(B + C) = (AB + AC), when
and 
Given :
and 
Matrix A is of order 2
2 , matrix B is of order 2
2 and matrix C is of order 2
2
To verify : A(B + C) = (AB + AC)
Formula used :

Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
If A is a matrix of order a
b and B is a matrix of order c
d ,then matrix AB exists and is of order a
d ,if and only if b = c
If A is a matrix of order a
b and B is a matrix of order c
d ,then matrix BA exists and is of order c
b ,if and only if d = a
B + C =
+
=
= ![]()
B + C = ![]()
Matrix A(B + C) is of order 2 x 2
A(B + C) =
= ![]()
A(B + C) =
= ![]()
A(B + C) = ![]()
For matrix AB, a = b = c = d = 2 ,matrix AB is of order 2 x 2
Matrix AB =
= ![]()
Matrix AB =
= ![]()
Matrix AB = ![]()
For matrix AC, a = b = c = d = 2 ,matrix AC is of order 2 x 2
Matrix AC =
= ![]()
Matrix AC =
= ![]()
Matrix AC = ![]()
Matrix AB + AC =
+
=
= ![]()
Matrix AB + AC = A(B + C) = ![]()
A(B + C) = (AB + AC)
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.






