Verify that A(B + C) = (AB + AC), when
and 
Given :
and 
Matrix A is of order 3
2 , matrix B is of order 2
2 and matrix C is of order 2
2
To verify : A(B + C) = (AB + AC)
Formula used :

Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
If A is a matrix of order a
b and B is a matrix of order c
d ,then matrix AB exists and is of order a
d ,if and only if b = c
If A is a matrix of order a
b and B is a matrix of order c
d ,then matrix BA exists and is of order c
b ,if and only if d = a
B + C =
+
=
= ![]()
B + C = ![]()
For Matrix A(B + C), a = 3,b = c = d = 2,thus matrix A(B + C) is of order 3 x 2
A(B + C) =
= 
A(B + C) =
= 
A(B + C) = 
For matrix AB, a = 3, b = c = d = 2 ,matrix AB is of order 3 x 2
Matrix AB =
= 
Matrix AB =
= 
Matrix AB = 
For matrix AC, a = 3, b = c = d = 2 ,matrix AC is of order 3 x 2
Matrix AC =
= 
Matrix AC =
= 
Matrix AC = 
Matrix AB + AC =
+
=
= 
Matrix AB + AC = A(B + C) = 
A(B + C) = (AB + AC)
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