Find the matrix A such that 
Given : 
To find : matrix A
Formula used :

Where cij = ai1b1j + ai2b2j + ai3b3j + ……………… + ainbnj
IF XA = B, then A = X-1B
. A = ![]()
A = ![]()
To find ![]()
Determinant of given matrix =
= 5(3) – (-7)(-2) = 15 – 14 = 1
Adjoint of matrix
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=
×
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A =
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A =
=
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A = ![]()
A = ![]()
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Couldn't generate an explanation.
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