Q4 of 123 Page 22

The area bounded by y = 2 – x2 and x + y = 0 is


- the blue shaded region above


To define the bounds, we need to find the points of intersection. We know that at the points of intersection, both the equations are satisfied.


⇒ x + y = 0


⇒ x + (2 – x2) = 0 (from the other equation)


So, x2 – x – 2 = 0 i.e., (x - 2)(x + 1) = 0 or x = -1,2


So, bounds are x = -1 to x = 2


Therefore, area shall be evaluated as –




(Ans)

More from this chapter

All 123 →
2

The area included between the parabolas y2 = 4x and x2 = 4y is (in square units)

 3

The area bounded by the curve y = loge x and x-axis and the straight line x = e is

 5

The area bounded by the parabola x = 4 – y2 and y-axis, in square units, is

 6

If An be the area bounded by the curve y = (tan x)n and the lines x = 0, y = 0 and x = π/4, then for x > 2