Q23 of 123 Page 22

The area bounded by the curve y = f(x), x-axis, and the ordinates x = 1 and x = b is (b – 1) sin (3b + 4). Then, f (x) is

So, the area enclosed from x = 1 to x = x (say) is (x – 1) sin (3x + 4)


⇒ A = ∫f(x) dx = F(x) = (x – 1) sin (3x + 4)


⇒ f(x) = F’(x) = sin (3x + 4) + 3(x – 1) cos (3x + 4) (Using u-v rule of differentiation)


(Ans)

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