The area of the region (in square units) bounded by the curve x2 = 4y, line x = 2 and x-axis is

Q22 of 123 Page 22

The area of the region (in square units) bounded by the curve x² = 4y, line x = 2 and x-axis is

x² = 4y, at y = 0, x = 0

So, our bounds are x = 0 and x = 2

Area A enclosed is –

A =

= 8/12, i.e., 2/3 (Ans)

The area bounded by the curve y = 4x – x² and the x-axis is

Area enclosed between the curve y² (2a – x) = x³ and the line x = 2a above x-axis is

The area bounded by the curve y = f(x), x-axis, and the ordinates x = 1 and x = b is (b – 1) sin (3b + 4). Then, f (x) is

The area bounded by the curve y² = 8x and x² = 8y is