A die is thrown. Find the probability of
getting an odd number
We know that,
Probability of occurrence of an event ![]()
As 1, 3, 5 are odd numbers up to 6, so the desired outcomes are 1, 3, 5, and total outcomes are 1, 2, 3, 4, 5, 6
Therefore, total no.of outcomes are 6, and total no.of desired outcomes are 3
Probability of getting an odd number ![]()
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Conclusion: Probability of getting an odd number when a die is thrown is ![]()
Couldn't generate an explanation.
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