In class, 30% of the students offered mathematics 20% offered chemistry and 10% offered both. If a student is selected at random, find the probability that he has offered mathematics or chemistry.
Given: Math students = 30%
Chemistry Students = 20%
Math & Chemistry both = 10%
To Find: P(Math or Chemistry)
Now, P(Math) ![]()
P(Chemistry) ![]()
P(Math ∩ Chemistry) ![]()
We know that,
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
Therefore,
P(Math ∪ Chemistry) = 0.30 + 0.20 – 0.10 = 0.40
Hence, number of students studying math or chemistry are 40%.
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