Q6 of 63 Page 976

If A and B are two mutually exclusive events such that P(A) = (1/2) and P(B) = (1/3), find P(A or B).

Given : A and B are mutually exclusive events


P(A) = , P(B) =


To find : P(A or B)


Formula used : P(A or B) = P(A) + P(B) - P(A and B)


For mutually exclusive events A and B, P(A and B) = 0


Substituting in the above formula we get,


P(A or B) = + – 0


P(A or B) =


P(A or B) =


More from this chapter

All 63 →
4

If A and B are two events associated with a random experiment such that P(A) = 0.25, P(B) = 0.4 and P(A or B) = 0.5, find the values of

(i) P(A and B)


(ii)


5

If A and B be two events associated with a random experiment such that P(A) = 0.3, P(B) = 0.2 and P(A ∩ B) = 0.1, find

(i)


(ii)


7

Let A and B be two mutually exclusive events of a random experiment such that P(not A) = 0.65 and P(A or B) = 0.65, find P(B).

 8

A, B, C are three mutually exclusive and exhaustive events associated with a random experiment.

If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).