Evaluate the following integrals:

To Find :

Now, can be written as

i.e.,

Here , let x – 2 = y dx = dy

Therefore, can be written as

Formula Used: = log |x +|+ C

Since is of the form with change in variable.

= log |y +|+ C

= log |y +|+ C

= 2 log |y +|+ C

Since , x – 2 = y and dx = dy

= 2 log |(x-2) +|+C Therefore,

= 2 log |(x - 2) +|+ C