Evaluate the following integrals:

To Find :

Now, let be written as (2x – 4) -1 and split

Therefore ,

=

=

Now solving,

Let = u dx =

Thus, becomes

Now , = = =

=

Now solving,

=

=

Let x – 2 = y dx = dy

Then becomes

Formula Used: = log |x +|+ C

Since is in the form of with change in variable.

Hence = log |y +|+ C

= log |y +|+ C

Now, since x – 2 = y and dx = dy

= log |(x-2) +|+ C

Hence = log |(x-2) +|+ C

Therefore , =

log |(x-2) +|+ C

=

log |x - 2 +|+ C