Evaluate the following integrals:
![]()
To Find :![]()
Now, let x be written as
-
(1 - 2x) and split
Therefore ,
= ![]()
=
+ ![]()
Now solving, ![]()
Let
= u
dx = ![]()
Thus,
becomes ![]()
Now ,
=
=
) = ![]()
=![]()
Now solving, ![]()
can be written as ![]()
i.e,
= ![]()
let 2x – 1 = y
dx = ![]()
Therefore ,
becomes ![]()
Formula Used:
=
+
+ C
Since
is of the form
with change in variable .
Hence,
=
+
+ C
=
+
+ C
Since , 2x – 1 = y and dx = ![]()
Therefore,
=
+
+ C
i.e,
=
+
+ C
hence ,
=
+
= =
+
+
+ C
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