Q10 of 78 Page 14

Mark the Correct alternative in the following:

The number of solutions of is


when x > 0

x2 + x-1 = 1


x2 + x - 2 = 0


(x-1) (x+2) = 0


x = 1, -2


when x < 0


x2 - x+1 = 1


x2 – x = 0


x(x-1) = 0


x = 0, 1


hence the given equation has 3 solutions and they are x = 0, 1, -1.

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