Q26 of 78 Page 15

Given




[∵ (a – b)2 = a2 – 2ab + b2]



We have i2 = –1 ⇒ 1 = –i2


By substituting 1 = –i2 in the above equation, we get





[∵ a2 – b2 = (a + b)(a – b)]





Thus, the roots of the given equation are.


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