Evaluate each of the following integrals as the limit of sums:
Since it is modulus function so we need to break the function and then solve it
it is continuous in [0,1]
let 
and 
here h=1/3n
=1/3
here h=2/3n
=2/3
f(x)=g(x)+h(x)
=(1/3)+(2/3)
=3/3
=1
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