Evaluate the following integrals

Let ![]()
Let,
![]()
=-2ax+5a+b
Hence -2a=-1 and 5a+b=2.
Solving these equations,
we get
and
.
We get,
![]()
Let ![]()
Let 5x-6-x2=t
⇒ (5-2x) dx=dt.
When x=2, t=0 and when x=3, y=0.
Hence ![]()

Let,
![]()


![]()
=π
Hence,
![]()
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