Evaluate the following integrals

Let ![]()
Let x=a tan2y
⇒ dx=2a tan y sec2y dy.
Also, when x=0, y=0
and when x=a, ![]()
Hence 
Using integration by parts, we get

Let tan y=t
⇒ sec2ydy=dt.
Also, when y=0, t=0
and when
, t=1.
Also, y=tan-1t
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Let ![]()


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Hence ![]()
Substituting value of I’ in I, we get
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