Lets write the measurement of 7 angles from the figure beside if XY||PQ.

Given that XY||PQ and cut by a transversal.

So, if two lines are parallel and cut by a transversal then the corresponding angles are equal,

Alternate interior angles are equal

Alternate exterior angles are equal,

Sum of co-interior angles is 180°.

∠2=50° (vertically opposite angles)

Now, as XY is a straight line,

∠2+∠3=180° (linear pair)

⇒ ∠3=180° -∠2

⇒ ∠3=180° -50°

⇒ ∠3=130°

∠1=∠3=130° (vertically opposite angles)

Also, ∠6=∠3=130° (corresponding angles)

∠7=∠2=50° (corresponding angles)

∠4=∠3=130° (alternate interior angles)

∠5=∠2=50° (alternate exterior angles)

Hence, ∠1=130°, ∠2=50°, ∠3=130°, ∠4=130°, ∠5=50°, ∠6=130° and ∠7=50°