In the figure beside PQ||RS, ∠BPQ=40°, ∠BPR=155° and ∠CRS=70°; let’s write the measurement of all the angles of APR![]()


Given that PQ||RS and ∠BPQ=40° and ∠BPR=155°
Also, ∠CRS=70°
Draw a line through A such that PQ||AY||RS
Since AB is a straight line ,
∠APB=180° (straight angle)
⇒ ∠BPR+∠APR=180°
⇒ 155° +∠APR=180°
⇒ ∠APR=180°-155°
⇒ ∠APR=25°…………..(1)
Since PQ||AY
So, ∠PAY=∠BPQ=40° (corresponding angles)
Similarly, AY||RS
So, ∠RAY=∠CRS=70° (corresponding angles)
Now, ∠PAR=∠PAY+∠RAY=40°+70°=110°
Now, in ∆APR,
∠PAR+∠APR+∠ARS=180°
⇒ 110°+25° +∠ARS=180°
⇒ 135° +∠ARS=180°
⇒ ∠ARS=180°-135°
⇒ ∠ARS=45°
Hence, ∠ARS=45°, ∠PAR=110° and ∠APR=25°
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