This year the students of Nandlal H.S school have passed 85% in Bengali, 70% in maths and 65% in both subject scoring A+. If the number of students are 120 then let’s work out how many students
(i) got A+ in both subjects
(ii) got A+ only in maths
(iii) got A+ in Bengali
(iv) did not get A+ in both subjects
Given: Percentage of students who got A+ in Bengali=85%
Percentage of students who got A+ in Maths=70%
Percentage of students who got A= in both subjects=65%
Total number of students =120
Tip: x% of y means ![]()
By using the given tip we can easily figure out the number of students who got A+
in subparts (i), (ii),(iii),(iv)
(i)
The no. of students who got A+ in both the subjects is
![]()
=78 students.
(ii)
The percentage of students who got A+ in Maths=70%
The percentage of students who got A+ in both subjects that is including maths and Bengali is=65%
Therefore, the percentage of students who got A+ only in Maths is=70-65
=5%
Therefore, the number of students who A+ only in Maths is
=6 students
(iii)
The percentage of students who got A+ in Bengali is=85%
Therefore, the number of students who A+ in Bengali is
![]()
=102 students
(iv)

From the Venn Diagram drawn it is evident that the percentage of students who did not get A+ is 10%
( Percentage of students not having A+= 100%-(percentage of students
having A+ in both
subjects + percentage of
students having A+ in
only Bengali and Maths)
= 100%-90%
=10%)
Therefore, the no. of students who do not have A+ is
=![]()
=12 students.
Couldn't generate an explanation.
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