The length of a rectangle is increased by 15% and the breadth is reduced by 15%. Let’s work out in percentage the increase or decrease of area.
Given: The percentage increment of the length of the rectangle=15%
The percentage decrement of the breadth of the rectangle=15%
Tip: if y is increased by x% then the new value of y is ![]()
![]()
: if y is decreased by x%, then the new value of y is ![]()
![]()
Let the length of the rectangle be “L” units.
Let the breadth of the rectangle be B units
Therefore, initially before any change in the lengths of both the length and breadth of the rectangle is
=![]()
Now, Using tip (i)
The new length of the rectangle will be:
=L
units =L
units
Now, Using tip (ii)
The new breadth of the rectangle will be:
=B
units. =B
units
Therefore, the new area of the rectangle will be:
=L
B![]()
=LB![]()
![]()
Therefore, the decrement in area= LB- LB![]()
![]()
=LB![]()
Therefore, percentage decrement in area,
=![]()
=![]()
=2.25%
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