Let's write the measurement of each interior and exterior angle of a regular polygon with 10 sides.

For Interior Angles

We know that, if a polygon has ‘n’ sides, then it divides in (n – 2) triangles.

We also know that, by angle sum property that

Sum of the angles of a triangle = 180°

∴, the sum of angles of (n – 2) triangle = (n – 2) × 180°

It is given that regular polygon has 10 sides

So,

= 8 × 18

= 144°

For Exterior Angles

It is given that regular polygon has 10 sides

Since, 10 sides of a polygon has 10 angles

and we know that, the sum of the exterior angles of a polygon is 360°

∴10 exterior angles of a regular polygon = 360°

= 36°