Q2 of 59 Page 194

O is any point inside the triangle ABC. Let’s prove that

AB+AC>OB+OC


Let us first draw a diagram for the above proof.


We know one basic fact about triangles that the sum of any two sides of a triangle is always greater than the third side.


So let us first consider Δ ABC


AB + AC > BC ……………………. (i)


Similarly let us consider the Δ OBC


OB + OC >BC ……………………. (ii)


Now let us subtract equation (ii) from equation (i)


(AB + AC) – (OB + OC) > BC – BC


(AB + AC) – (OB + OC) > 0


AB + AC > OB + OC


Hence Proved.


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