O is any point inside the triangle
ABC. Let’s prove that
AB+AC>OB+OC
Let us first draw a diagram for the above proof.

We know one basic fact about triangles that the sum of any two sides of a triangle is always greater than the third side.
So let us first consider Δ ABC
AB + AC > BC ……………………. (i)
Similarly let us consider the Δ OBC
OB + OC >BC ……………………. (ii)
Now let us subtract equation (ii) from equation (i)
(AB + AC) – (OB + OC) > BC – BC
(AB + AC) – (OB + OC) > 0
AB + AC > OB + OC
Hence Proved.
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