Q11 of 15 Page 118

In a vessel of beverage the ratio of measurement of syrup and water is 5:2. Let’s work out what part of the drink should remove and replaced by water so that the volume of syrup and water becomes equal.

Let the mixture of syrup and water is “x” litres.


So,


Volume of syrup in the mixture


Volume of water in the mixture


Let “y” = Volume of mix taken out = Volume of water added


When a part of drink is taken out:


In the drink the ratio will remain same:


So,


Volume of syrup is


Volume of water is


After a part is taken out:


Volume of syrup in vessel


Volume of water in vessel


After water is added,


Volume of water


According to the question:


Volume of water added = volume of syrup




⇒ 2x – 2y + 7y = 5x – 5y


⇒ 2x + 5y = 5x – 5y


⇒ 2x + 5y = 5x – 5y


⇒ 5y + 5y = 5x – 2x


⇒ 10y = 3x



Hence the volume of water added is 3/10 part of the vessel.


More from this chapter

All 15 →
9

Two different types of brass coating Copper and Zinc in the ratio of measurement 8:3 and 15:7 respectively. Let’s work out what the ratio of measurement of Copper and Zinc will be if these two types of brass are mixed together in the ratio of measurement 5:2.

 10

Two different types of stainless steel contain Chromium and Steel in the ratio of measurement of 2:11 and 5:21 respectively. Let’s work out in what proportion these two types of steel should be mixed, so that the ratio of measurement of Chromium and Steel becomes 7:32.

12

Let’s see the table below, write in mathematical language and try to find out the answer.

 13

There are three kinds of liquid in a beverage of 700 liters. The ratio of measurements of the first and the second liquids is 2:3 and the ratio of measurement of the second and the third liquid is 4:5. Let’s work out the ratio in which the first and second liquid will be mixed so that the ratio of measurement of the three liquids become 6:5:3 in the new beverage.