Q3 of 69 Page 10

The angles of a triangle are (x-40)°, (x-20)° and. Find the value of x.

Given that,

The angles of the triangle are (x – 40o), (x – 20o) and ( – 10o)


We know that,


Sum of all angles of triangle is 180o.


Therefore,


x – 40o + x – 20o + – 10o = 180o


2x + – 70o = 180o


= 250o


5x = 250o * 2


5x = 500o


x = 100o


Therefore, x = 100o


More from this chapter

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1

In a Δ ABC, if ∠A = 55°, ∠B = 40°, find ∠C

 2

If the angles of a triangle are in the ratio 1 : 2 : 3, determine three angles.

 4

The angles of a triangle are arranged ascending order of magnitude. If the difference between two consecutive angles is 10°, find the three angles.

 5

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.