Q20 of 69 Page 9

In Fig. 9.45, if AB ⊥ BC, then x =

Given,

AB is perpendicular to BC so ∠B = 90o


∠CED = 32o (Vertically opposite angles)


In


∠BDE + ∠BED + ∠DBE = 180o


x + 14o + 32o + x + 90o = 180o


2x = 44o


x = 22o

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