Q22 of 69 Page 9

In Fig. 9.47, for which value of x is l1 || l2?

Since,

l1‖ l2


And,


AB cuts them so,


∠DBA = ∠BAE = 78o


∠BAC + 35o = 78o


∠BAC = 43o


In


∠BAC + ∠ABC + ∠ACB = 180o


43o + x + 90o = 180o


x = 47o

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