Q14 of 46 Page 1

Find all the zeroes of 2x4 – 3x3 – 3x2 + 6x – 2, if it is given that two of its zeroes are 1 and

Given zeroes are 1 and

So, (x – 1) and are the factors of 2x4 – 3x3 – 3x2 + 6x – 2






Consequently, 2x2 – 3x + 1 is also a factor of the given polynomial.


Now, let us divide 2x4 – 3x3 – 3x2 + 6x – 2 by 2x2 – 3x + 1


The division process is



Here, quotient = x2 – 2


= (x – 2)(x + 2)


So, the zeroes are -2 and 2


Hence, all the zeroes of the given polynomial are -2, 1/2, 1 and 2.


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