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Chemistry
14. Biomolecules
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Q42 of 71 Page 209

How do you explain the presence of five —OH groups in glucose molecule?


When glucose is treated with acetic anhydride (CH3CO)2O, in the presence of ZnCl2, it undergoes acetylation to form glucose pentaacetate which confirms the presence of five –OH groups.


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14. Biomolecules
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