Consider a pair of identical pendulums, which oscillate with equal amplitude independently such that when one pendulum is at its extreme position making an angle of 2° to the right with the vertical, the other pendulum makes an angle of 1° to the left of the vertical. What is the phase difference between the pendulums?
For simple harmonic motion,
where x = displacement
w= angular velocity
A = amplitude
δ = phase
Given:
for both the pendulum the amplitude is given to same and ∵ they are identical, their length are the same and thus their angular velocity are also same as for the pendulum 
, g=acceleration due to gravity and length of the pendulum is given as L.
∴ pendulum 1 we can write,
At 
∴ 
-----(1)
pendulum 1 we can write,
At 
∴ 
-----(2)
For phase difference we subtract (2) from (1), we get,
∴ the phase difference between the two pendulum is of 
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