A cylindrical log of wood of height h and area of cross-section A floats in water. It is pressed and then released. Show that the log would execute S.H.M. with a time period.
T = 2π √![]()
where m is mass of the body and ρ is density of the liquid.
Here we apply the concept of buoyant force
Let the wood
part of the height of the wood be immersed into the water
Here the wood log experiences a buoyant force which is given as,
,
where ρ =density of wood log, V=volume of the water displaced by wood now at equilibrium, the buoyant force is balanced by the weight, i.e.,
![]()
------(1)
Now let the wood be displaced by
depth into the water,
∴ the volume of the water displaced by the wood is,![]()
∴ the buoyant force ![]()
∴ there acts net restoring force on the wood log,
![]()
Putting equation (1) in the above we get,
-------(2)
∵
is proportional to ![]()
∴ wood performs a simple harmonic motion
Now the in S.H.M., we have ![]()
Comparing this equation with equation (2) we get,
![]()
For S.H.M, Time period ![]()
Substituting the value of k, we get,

Hence proved.
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