Measure of two quantities along with the precision of respective measuring instrument is A = 2.5 m s–1 ± 0.5 m s–1 B = 0.10 s ± 0.01 s The value of A B will be
Given,
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Let, X=AB
X=AB=![]()
Precision can be calculated by,
If
is the error in the X,
be the error in A and
be the error in B, then relative error is calculated as
.
Therefore now,
(For the formula part refer to
NCERT class 11 part 1 unit
and measurement chapter)
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Rounding off 0.075 to two significant figures we get,
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Therefore, the value of AB is
.
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