The volume of a liquid flowing out per second of a pipe of length l and radius r is written by a student as
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where P is the pressure difference between the two ends of the pipe and η is coefficient of viscosity of the liquid having dimensional formula ML-1 T-1. Check whether the equation is dimensionally correct.
Given:
The equation for volume flow per second V= ![]()
The for the equation to be dimensionally correct the the dimensional formula of the equation must be equal to the dimensional formula of the volume flow per second.
Thus dimensional formula of ![]()
Dimensional formula of pressure ![]()
Dimensional formula of coefficient of viscosity ![]()
Dimensional formula of length ![]()
Dimensional formula of radius ![]()
Thus dimensional formula of RHS of the equation
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And dimensional formula of LHS
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Therefore, LHS = RHS
Thus, the given equation is dimensionally correct.
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