A man runs across the roof-top of a tall building and jumps horizontally with the hope of landing on the roof of the next building which is of a lower height than the first. If his speed is 9 m/s, the (horizontal) distance between the two buildings is 10 m and the height difference is 9 m, will he be able to land on the next building? (take g = 10 m/s2)
For horizontal motion
Initial velocity in the vertical direction (uV) = 0 m/s
Initial velocity in the horizontal direction (uH) = 9 m/s
Distance between the two buildings = x(t) = 10m
Height difference between two buildings = y(t) = 9m
Acceleration (a) = g = 10 ms-2{Downward direction is assumed to be positive}
The motion in the vertical direction.
Horizontal distance travelled in time (t)
For horizontal motion
Initial velocity (uH) = 9 ms-1
Horizontal distance covered (H) in time t,
This is more than 10 m (the horizontal difference between the buildings) and thus the man will be able to make the jump.
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