The free surface of oil in a tanker, at rest, is horizontal. If the tanker starts accelerating the free surface will be titled by an angle θ. If the acceleration is a m s-2, what will be the slope of the free surface?

Every surface aligns itself such that it is perpendicular to the net force so that the net force along the surface is zero.
When the tanker moves with acceleration a, a pseudo force acts on the oil in the opposite direction.
Here,
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So, the slope of the free surface is a/g
Couldn't generate an explanation.
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