If a drop of liquid breaks into smaller droplets, it results in lowering of temperature of the droplets. Let a drop of radius R, break into N small droplets each of radius r. Estimate the drop-in temperature.
Here, N droplets form a bigger drop.
So, volume of bigger drop = sum of the volumes of the smaller drops.
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Now, energy released is equal to the difference in the surface energies.
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Now, if
is the temperature drop, m is the mass and c is the specific heat then,
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is negative as R>r.
Hence, the drop-in temperature is, ![]()
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