The surface tension and vapour pressure of water at 20°C is 7.28×10-2 Nm-1 and 2.33×103 Pa, respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at 20°C?
Given:
Surface Tension = T =7.28×10-2 Nm-1
Vapour pressure = P = 2.33×103 Pa
Radius = r
Now,
Excess pressure = 2T/r
We know, the drop will evaporate when excess pressure is equal to vapour pressure.
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