Question is multiple choice question
When one mole of CoCl3.5NH3 was treated with excess of silver nitrate solution, 2 mol of AgCl was precipitated. The formula of the compound is:
Since 2 moles of AgCl was precipitated out, the 2 moles of Cl- should be available as the ionisable ion outside the coordination sphere. In this way only, Cl- from the coordination compound would be available for precipitation. Thus the formula is-
[Co(NH3)5Cl]Cl2
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