Q6 of 40 Page 1

The sum of the zeroes of the polynomial 2x2 – 8x + 6 is

2x2 – 8x + 6 = 2(x2 – 4x + 3)


⇒ 2(x2 – 4x + 3) = 0


⇒ x2 – 4x + 3 = 0


⇒ x2 – x – 3x + 3 = 0


⇒ x(x – 1) - 3(x – 1) = 0


⇒ (x – 3) × (x – 1) = 0


⇒ x = 1, 3


Sum of zeroes = 4

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