Q35 of 40 Page 1

Find two consecutive positive integers sum of whose squares is 365.

Let the two consecutive integers be x and x + 1,


x2 + (x + 1)2 = 365


x2 + x2 + 2x + 1 = 365


2x2 + 2x – 364 = 0


x2 + x – 182 = 0




x = 13, -14


But x should be positive. So, x = 13


The consecutive integers are 13 and 14.


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