Find two consecutive positive integers sum of whose squares is 365.
Let the two consecutive integers be x and x + 1,
⇒ x2 + (x + 1)2 = 365
⇒ x2 + x2 + 2x + 1 = 365
⇒ 2x2 + 2x – 364 = 0
⇒ x2 + x – 182 = 0

![]()
⇒ x = 13, -14
But x should be positive. So, x = 13
The consecutive integers are 13 and 14.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
