Q4 of 94 Page 442

How much energy is released in the following reaction:

7Li + p → α + α.


Atomic mass of 7Li = 7.0160 u and that of 4He = 4.0026 u.


Given,


Atomic mass of 7Li = 7.0160 u


Mass of proton = 1.007276 u


Atomic mass of 4He = Mass of α particle = 4.0026 u


∴



So, ΔM = 0.018076u


Binding Energy [Where ]




Hence, the binding energy for the reaction is 16.83 MeV


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