Q7 of 59 Page 395

The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field between the cathode and the target.

Given:


Distance between the filament and the target in the X-ray tube d=1.5m


cut-off wavelength= 30pm


Energy(E) is given by



thus,





Now,


Electric field = V/d=


=


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