(a) Account for the following:
(i) BiH3 is the strongest reducing agent in Group 15 elements hydrides.
(ii) Cl2 acts as a bleaching agent.
(iii) Noble gases have very low boiling points.
(b) Draw the structures of the following:
(i) H4P2O7
(ii) XeOF4
OR
(a) Although nitrogen and chlorine have nearly same electronegativity yet nitrogen forms hydrogen bonding while chlorine does not. Why?
(b) What happens when F2 reacts with water?
(c) Write the name of the gas evolved when Ca3P2 is dissolved in water.
(d) Write the formula of a noble gas species which is isostructural with IBr2-.
(e) Complete the equation: [Fe(H2O)6]2+ + NO →
(a)
(i) BiH3 is the strongest reducing agent in Group 15 elements hydrides because stability of hydrides decreases down the group as the size of cations increases and hence reducing character of hydrides increases.
(ii) Cl2 acts as a bleaching agent because it liberates nascent oxygen when reacted with water and that nascent oxygen converts colored substance into colorless substance.
Cl2 + H2O → HCl + HOCl
HOCl → HCl + (O)
Colored substance + (O) → colorless
(iii) Noble gases have very low boiling points because only type of interatomic interactions present in these elements is weak dispersion forces.
(b)
(i) H4P2O7

(ii) XeOF4

OR
(a) Although nitrogen and chlorine have nearly same electronegativity yet nitrogen forms hydrogen bonding while chlorine does not because size of nitrogen is smaller than chlorine because of which electron density per unit volume on N atom is higher than that of Cl atom.
(b) It oxidses H2O to O2.
2F2 + 2H2O → O2 + 4H+ + 4F-
(c) Gas evolved when Ca3P2 is dissolved in water is phosphine.
Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3
(d) Noble gas species which is isostructural with IBr2- is XeF2. Both have 2 bond pairs and 3 lone pairs and form a linear structure.
(e) [Fe(H2O)6]2+ + NO → [Fe(H2O)5(NO)]2+ + H2O
(brown ring)
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