How much charge in Faraday is required for the reduction of 1 mole of Ag+ to Ag?
We know that, Charge =
, where n is the number of electrons and F is the Faraday constant (96486)
• Thus, when n=1, the amount of charge required for the reduction of Ag+ to Ag is Charge = 1
96486.
• Total charge = 96486 F.
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