Write the structures of A, B, C and D in the following reactions:
(a)

(b) Distinguish between the following:
(i) CH3-CO-CH2CH3 and CH3-CH2-CH2-CHO
(ii) Ethanal and Ethanoic acid
(c) Write the structure of 4-Chloropentan-2-one
OR
(a) Write the structures of the main products when Propanal (CH3-CH2-CHO) reacts with the following reagents:
(i) Zn-Hg/ conc. HCl
(ii) H2N-OH/H+
(iii) HCN
(b) Arrange the following in decreasing order of their reactivity towards nucleophilic addition reaction
HCHO, CH3-CO-CH3, CH3-CHO
(c) Give the simplest chemical test to distinguish between the following pairs of compounds:
C6H5CHO and C6H5-CO-CH3
(a)
A – CH3COCl
Acetic acid reacts with phosphorous pentachloride to give Acetyl chloride.
B – CH3CHO
Acetyl chloride undergoes Rosenmund reduction with Pd in the presence of BaSO4 to give Acetaldehyde.
C – CH3CH(OH)CH3
Acetaldehyde reacts with Grignard reagent to give 2-Propanol.
D – CH3CH2OH
Acetaldehyde gets reduced in the presence of Lithium aluminium hydride to give Ethanol.
(b)
(i)
• Butanal is an aldehyde and answers Tollens’ reagent but Ethyl methyl ketone does not answer.
• Upon reaction with Tollens reagent, Butanal gives silver mirror.
(ii)
• Ethanoic acids answers the litmus test by changing red litmus blue whereas Ethanal does not answer this test as it is neutral in nature.
• This test is used for distinguishing Ethanal from Ethanoic acid.
(iii) 4-Chloro-pentan-2-one

OR
(a)
(i) Propanal reacts with Zinc amalgam in the presence of conc. HCl to under goClemmenson Reduction and give the corresponding hydrocarbon, in this case propane.
CH3-CH2-CH3
(ii) Propanal reacts with Hydroxylamine to give the oxime of propane.
CH3-CH2-CH=NOH
(iii) Propanal reacts with HCN to undergo a nucleophilic reaction giving a cyanohydrin.
CH3CH2CH(OH)CN
(b)
• Aldehydes undergo nucleophilic addition reactions more easily than ketones.
• Formaldehyde undergoes nucleophilic addition easily than acetaldehyde.
• Thus, the decreasing order of reactivity is
HCHO>CH3CHO>CH3-CO-CH3
(c)
• Acetophenone reacts with Iodoform test to prove the presence of CH3C=O group.
• This answers by giving a yellow precipitate.
• Benzaldehyde does not answer Iodoform test.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.