Calculate emf and
G for the following cell at 298 K
Mg (s)| Mg2+ (0.01M) || Ag+ (0.0001M) | Ag (s)
Given: E˚(Mg2+/Mg) = -2.37 V and E˚(Ag+/Ag) = +0.80 V
OR
(a) The conductivity of 0.001 mol/L solution of CH3COOH is 4.95
10-5 S/cm. Calculate it’s molar conductivity and degree of dissociation.
Given,
(H+) = 349.6 S cm/mol
(CH3COO-) = 40.9 S cm/mol
(b) What is a fuel cell? Write its one advantage over the other ordinary cells.
We know that,
E˚cell = E˚C - E˚A
Ecell = 0.80 – (-2.37)
Ecell = 3.17 V
Anode reaction: Mg
Mg2+ + 2e-
Cathode reaction: 2Ag+ + 2e-
2Ag (By multiplying by 2 to equate the number of electrons)
Cell reaction: Mg + 2Ag+
Mg2+ + 2Ag
According to Nernst Equation,
Ecell = E˚cell –
log [Mg2+]/[Ag+]2
= 3.17 –
log [0.1]/ [0.0001]2
= 3.17 – 0.0295 log [0.1]/ [1x 10-8]
= 3.17 – 0.0295[ log0.1 + log108]
= 3.17 – 0.0295[-1 + 8]
= 3.17 – 0.0295(7) = 3.17 – 0.2065
Ecell = 2.9635 V
G = -nfE˚cell
= -2 x 96500 x 3.17
G = -611.810 kJ/mol
OR
(a) We know that,
C = 0.001 mol/L and k = 4.95 x 10-5 S/cm
Molar conductivity = ![]()
= 4.95
10-5 x ![]()
= 49.5 S cm2/mol
CH3COOH = CH3COO- + H+
(CH3COOH)=
(CH3COO-) +
(H+)
= 40.9 + 349.6
= 390.5 S cm2/mol
Degree of dissociation =
m /
m
= ![]()
Degree of dissociation = 0.12
(b)
• A fuel cell is defined as a class of devices that converts chemical energy directly into electricity by chemical reactions.
• An example is a H2O2 fuel cell which was also used to produce energy during the Apollo Space Program.
• Fuel cells have higher efficiency than ordinary cells. They also do not produce a lot of pollution.
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