a. Predict the main product of the following reactions :
i. 
ii. 
iii. ![]()
b. Give a simple chemical test to distinguish between
c. Why is alpha (α) hydrogen of carbonyl compounds acidic in nature?
OR
a. Write the main product formed when propanal reacts with the following reagents :
i. 2 moles of CH3OH in presence of dry HCl
ii. Dilute NaOH
iii. H2N – NH2 followed by heating with KOH in ethylene glycol
b. Arrange the following compounds in increasing order of their property as indicated :
i. F - CH2COOH, O2N - CH2COOH, CH3COOH, HCOOH - acid character
ii. Acetone, Acetaldehyde, Benzaldehyde, Acetophenone - reactivity towards addition of HCN
a. (i)

(ii)

(iii) ![]()

b. Iodoform test is done to distinguish between these two compounds. On adding NaOH / I2 and heat, acetophenone forms yellow ppt. of iodoform(CHI3) whereas benzophenone does not.
c. Alpha (α) hydrogen of carbonyl compounds is acidic in nature due to resonance stabilisation of conjugate base of carbonyl compound
OR
a. (i) When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.
C2H5−CHO+2CH3OH→C2H5−CH(OCH3)2
(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOHand forms 3-hydroxy-2-methyl pentanal.
C2H5−CHO+ NaOH (dil) →CH3CH2CH (OH) CH (CH3) CHO
(iii) The carbonyl group of propanal is reduced to CH2 group on treatment with hydrazine followed by heating with KOHin ethylene glycol and the product formed will be propane (CH3CH2CH3)
b.
(i) increasing acid character order is
CH3COOH < HCOOH < FCH2COOH < O2N-CH2COOH
(ii) increasing order of reactivity towards addition of HCN
Acetophenone < Benzaldehyde < acetone < acetaldehyde
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