Write the IUPAC name of the following compound:
First we resolve the given compound by marking the carbon atoms and then try to find the parent chain.
We get this

Next we number the carbon atoms in the parent chain.

We see there are 3 carbon atoms in the parent chain, so there must be ‘prop’ in the name.
Also there are 2 substituents. One –CH3 (methyl) at 2nd carbon atom and a –Br (bromo) at 3rd carbon.
Now going alphabetically, higher priority is given to ‘bromo’.
So the IUPAC name stands as
3-bromo-2-methyl propene or 3-bromo-2-methyl prop-1-ene.
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